Home Screen

[omoba]

Hi,

How do I make an app automatically run on booting up/turning on my tablet?

How do I open an from another app? In order words I am running "app A" and while running that, I want to open "app B" from with "app A". Is it possible.

Eg. If an "app A" contains books; I want to put a button at the bottom of "app A" screen that links to "app B" which is a dictionary. When done with "app B", I can close it and automatically, I am back to "app A"

Thanks

 

[NJDude]

Hi,

How do I make an app automatically run on booting up/turning on my tablet?

You will need to create a service and set it to "start at boot", the service will start your app.

How do I open an from another app? In order words I am running "app A" and while running that, I want to open "app B" from with "app A". Is it possible.

Eg. If an "app A" contains books; I want to put a button at the bottom of "app A" screen that links to "app B" which is a dictionary. When done with "app B", I can close it and automatically, I am back to "app A"

Thanks

You need to use intents to do that, for example, put the following code on a button click event and it will open the YouTube app.

i.Initialize(i.ACTION_VIEW, "")
i.SetComponent("com.google.android.youtube/.HomeActivity")
StartActivity(i)

 

[Erel]

1. Use a service and check Project - Service properties - Start at boot.
2. You should create an Intent with the target application component (package name and activity) and then call StartActivity.

 

[omoba]

Thanks

This might be obvious but is there a tutorial on creating services and how to set it to boot on startup?

 

[NJDude]

To set a service to start at boot you have to do this in the IDE: Project -> Service Properties -> Start at boot.

For samples, just use the search function of the forum, you'll find quite a few.