Android Question Is there a method like Picturebox.point(x,y) in VB6

[Mscal]

Hi,everyone.At first I'm sorry for my stupid,but can you tell me if there a method used like Picturebox.point(x,y) in VB6?
For example
I have a EX.jpg,i want to load it in imageview or other something,then i can check every point's color.
How can i do it?

 

[Eme Fibonacci]

Dim b As Bitmap
b.Initialize(File.DirAssets,"image.jpg")
      
'Get Pixel
pixel=b.GetPixel(x,y)
  
'Use canvas to draw point.
Dim c As Canvas
c.Initialize(imageview1)
  
c.DrawPoint(x,y,color)

 

[Mscal]

Dim b As Bitmap
b.Initialize(File.DirAssets,"image.jpg")
     
'Get Pixel
pixel=b.GetPixel(x,y)
 
'Use canvas to draw point.
Dim c As Canvas
c.Initialize(imageview1)
 
c.DrawPoint(x,y,color)

thank you very much.

 

[Mscal]

Dim b As Bitmap
b.Initialize(File.DirAssets,"image.jpg")
     
'Get Pixel
pixel=b.GetPixel(x,y)
 
'Use canvas to draw point.
Dim c As Canvas
c.Initialize(imageview1)
 
c.DrawPoint(x,y,color)

I tested it and get color,but the value is minus.How can i convert it to RGB ?

 

[Mscal]

Dim b As Bitmap
b.Initialize(File.DirAssets,"image.jpg")
     
'Get Pixel
pixel=b.GetPixel(x,y)
 
'Use canvas to draw point.
Dim c As Canvas
c.Initialize(imageview1)
 
c.DrawPoint(x,y,color)

well，I get pure White=-1 and pure black=-16777216.I think i can get the VB6 like value when add 16777216

 

[Erel]

32 bit color to ARGB: https://www.b4x.com/android/forum/threads/get-the-rgb-color-from-getpixel.56760/#post-357302