use of square root in code.

[cdeane]

Can you explane to me how to find the root to this ploblem?

textbox1.Text=((Textboxm.Text*144*Textboxy.Text)+(Textboxc.Text^2))/cPI

Ex.

M=.00185
Y=6666.66
C=4

the root of 570.4 should come out to 23.8

 

[agraham]

textbox1.Text=(((Textboxm.Text*144*Textboxy.Text)+(Textboxc.Text^2))/cPI)^0.5

The square root is the power of 1/2 = 0.5

 

[klaus]

The square root function is Sqrt(x)

[FONT=Courier New][SIZE=2][FONT=Courier New][SIZE=2]textbox1.Text=[/SIZE][/FONT][/SIZE][/FONT][FONT=Courier New][SIZE=2][COLOR=#0000ff][FONT=Courier New][SIZE=2][COLOR=#0000ff][FONT=Courier New][SIZE=2][COLOR=#0000ff]Sqrt[/COLOR][/SIZE][/FONT][/COLOR][/SIZE][/FONT][/COLOR][/SIZE][/FONT][FONT=Courier New][SIZE=2][FONT=Courier New][SIZE=2]((Textboxm.Text*[/SIZE][/FONT][/SIZE][/FONT][FONT=Courier New][SIZE=2][COLOR=#800080][FONT=Courier New][SIZE=2][COLOR=#800080][FONT=Courier New][SIZE=2][COLOR=#800080]144[/COLOR][/SIZE][/FONT][/COLOR][/SIZE][/FONT][/COLOR][/SIZE][/FONT][FONT=Courier New][SIZE=2][FONT=Courier New][SIZE=2]*Textboxy.Text+Textboxc.Text^[/SIZE][/FONT][/SIZE][/FONT][FONT=Courier New][SIZE=2][COLOR=#800080][FONT=Courier New][SIZE=2][COLOR=#800080][FONT=Courier New][SIZE=2][COLOR=#800080]2[/COLOR][/SIZE][/FONT][/COLOR][/SIZE][/FONT][/COLOR][/SIZE][/FONT][FONT=Courier New][SIZE=2][FONT=Courier New][SIZE=2])/[/SIZE][/FONT][/SIZE][/FONT][FONT=Courier New][SIZE=2][COLOR=#800080][FONT=Courier New][SIZE=2][COLOR=#800080][FONT=Courier New][SIZE=2][COLOR=#800080]cPI[/COLOR][/SIZE][/FONT][/COLOR][/SIZE][/FONT][/COLOR][/SIZE][/FONT][FONT=Courier New][SIZE=2][FONT=Courier New][SIZE=2])[/SIZE][/FONT][/SIZE][/FONT]

Best regards.

 

[cdeane]

Thanks agraham