Hi
Is there a problem with the following;
dim adata() as string
adata = regex.split(".","AAAA.BBBB")
adata = regex.split(".","5606.0198")
The length of adata is 0 ????
It would appear the 'Pattern' does not want to split the string using a period (.)
I cant believe this would be true !
J.
Is there a problem with the following;
dim adata() as string
adata = regex.split(".","AAAA.BBBB")
adata = regex.split(".","5606.0198")
The length of adata is 0 ????
It would appear the 'Pattern' does not want to split the string using a period (.)
I cant believe this would be true !
J.