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on the desktop but am struggling on Android because Regex.IsMatch in Java seems behave differently ito... library I just do this and it seems to work fine Regex1.New1("del") If Regex1.IsMatch...
link: that discussion was not limited to regex approaches to the search problem, and veered off in a direction that has...
link: blank when I try to visualise the outcome of declarative style things like HTML, XML, XAML, Regex etc...
link: To me that did not seem to be a requirement (original code looked like it was processing one line at...

I'm still wondering what the higher-level goal is. It sounds like you're looking to scrap...
link: be looking for the word "high" rather than all words. Did you eventually wrangle regex...
link: at start of line Dim mat As Matcher = Regex.Matcher(pat, SampleText) Do While mat.Find Log(mat...
link: IsMatch2 compares pattern to the entire string. Matcher finds occurrences of pattern within...

In b4j, the code works correct for me and filterd 'ä, ö, ü'. In b4a it doesn't... If Regex.IsMatch("+", tf1.Text) = False...
link: Use this pattern: + The Android implementation is actually more correct in this case....
link: I tried to check a textfield, if the text doesn't contains illegal characters for an URL.......
link: What exactly are you trying to implement?...

doesn't work: Log("1 works ?: " & Regex.IsMatch2(ptrn, Regex.CASE_INSENSITIVE... The 1st log Regex.IsMatch2 will return False even if the next two ones return a match. now try to...Hi, I'm not sure if it's a bug or if I misunderstood how the regex works, but try...
link: No bug here. Thanks for your explanation, sorry I misread the documentation....
link: No bug here. See Regex.IsMatch documentation: http://www.b4x.com/android/forum/pages/results/?query...

(Array(rx.CharDigit, "abcdefABCDEF")).AppendAtLeastOne Log(Regex.IsMatch(rx.Pattern, "0xABcdef123")) 'True Log(Regex.IsMatch(rx.Pattern, "312123")) 'False Log(Regex..."d23df""$ Log(Regex.IsMatch(rx.Clear.AppendEscaped(s).Pattern, s)) 'true ...This class is compatible with B4A, B4i and B4J. Regex is a very powerful tool for parsing strings. However the regex syntax can be a bit difficult if you are not using regex regularly. Reading...

.Length - 1 If Regex.IsMatch("\p{InCombiningDiacriticalMarks}", n.CharAt(i)) = False... accents Based on this link: http://stackoverflow.com/questions/5697171/regex-what...

string is formatted in a format similar to: 12-31-2010 Log(Regex.IsMatch("\d\d-\d\d-\d\d\d\d", "11-15-2010")) 'True Log(Regex.IsMatch("\d\d-\d\d-\d\d\d\d"... Regex. You can write Regex followed by a dot to see the available methods. All methods accept.... Both options can be combined by calling Bit.Or(Regex.MULTILINE, Regex.CASE_INSENSITIVE). Matching the whole string IsMatch and IsMatch2 are good to validate user input. The result of these methods...

= False Select True Case Regex.IsMatch("(^\d{7})($)", CIF.ToUpperCase) Dim Matcher1 As Matcher = Regex.Matcher("(^\d{7})($)", CIF.ToUpperCase... = Matcher1.Group(2) = Digit Case Regex.IsMatch("(^)(\d{7})(\d$)", CIF.ToUpperCase) Dim Matcher1 As Matcher = Regex.Matcher("(^)(\d{7})(\d$)", CIF.ToUpperCase... = Matcher1.Group(3) = Checksum Case Regex.IsMatch("(^)(\d{7})($)", CIF...

Vorrei controllare che una stringa contenga solo numeri da 0 a 9 senza punti o spazi cone Regex. Ho trovato questo : dim test as string = "00000a" log (Regex.IsMatch("",test)) torna sempre false non funziona....
link: Dim test as string = "00000a" log (Regex.IsMatch("+",test)) puoi anche usare...

Private Sub EmailAddressCheck(email As String) As Boolean Return Regex.IsMatch("^*@*\.*$",email) End Sub If EmailAddressCheck("[email protected]") = True Then Log("E...
link: It's for B4J only; correct me if I'm wrong. No. If Regex.IsMatch(".+@.+\..+"...
link: If Regex.IsMatch(".+@.+\..+", req.GetParameter("email")) = False Then...
link: If Regex.IsMatch(".+@.+\..+", req.GetParameter("email")) = False Then...