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If you write: listB.AddAll(listA) The contents of listA is added to the contents of listB. The clear method removes all the items from the list (listB) So now listA remains the same!
link: Sub Process_Globals Private fx As JFX Private MainForm As Form Private listA As List Private listB As List End Sub Sub AppStart

newlist.As(List).AddAll(l) this snippet should return already a declared list named newlist with all items added from list "l" ITS A WISH!!
link: i would like this to work without declaring the object newlist newlist.As(List).AddAll(l) Log(newlist.Size) code that is needed now Dim
link: yes this solution is good to create a new list but not to copy 1 list to another. if i want to copy 1 list to a second list i will need to initialize
link: Unless you need to later add or remove elements: Dim newlist As List = Array("aa", "bb") In other cases, you can add a sub that creates the object

This works: Dim lst As List lst.Initialize lst.AddAll(File.ListFiles(File.DirDocuments)) lst.Sort(True) Log(lst)

i don't fully agree with the selections on the list, but i would use regex.split() and list.addall(). i'm guessing the string uses crlf (or possibly "\r\n", depending). so split the string on crlf to get an array of strings and then create a list and call addall. dim result as string = job.getstrin

File.ListFiles returns a read-only list (see the help box). AddAll will indeed work: Dim List1 As List List1.Initialize List1.AddAll(File.ListFiles(...))
link: Hi: Without knowing why the error is produced (and that's probably what you want to know, instead another solution), have you tried with: AddAll (L
link: Yes, I knew that thx, but it needed to add a suffix to each filename. AddAll did not work if I tried to do it to the list returned by listfiles. But

Quiz: What is the difference between: Dim MyList As List MyList.Initialize MyList.AddAll(Array ("no", "yes","ooo","test","yyy","nnn")) And: Dim MyList As List = Array ("no", "yes","ooo","test","yyy","nnn") ?
link: If we are tabulating the number of ways, here is another: Dim MyList As List MyList.Initialize MyList.AddAll(Array ("no", "yes","ooo","test","yyy","nn

Here you go @Arf. Below is an example of a list. I would read your values from a database if possible though. 'Example Dim Listy As List Listy.Initialize Listy.AddAll(Regex.Split(", ", "3.0, 1.3876, -0.0221, -0.0832, 3.25, 1.2621, -0.0191, -0.0616, 3.5, 1.1460, -0.0167, -0.0420"

You are welcome. AND there is an even more "simpler" but not so practical way. if the number of list is known you can create something like this: Sub AppStart (Form1 As Form, Args() As String) MainForm = Form1 MainForm.SetFormStyle("UNIFIED") 'MainForm.RootPane.LoadLayout("Layout1") 'Load the la
link: MainForm.Show Dim list1 As List : list1.initialize Dim list2 As List : list2.initialize Dim list3 As List : list3.initialize list1.AddAll( Array As
link: What's the easiest way, in B4J, to refer to an element in a nested list? So specifically, if you had List1.AddAll( Array As String( "one", "two", "f

vedi se ti piace private Sub sRandomAzzardoMilitare Dim lst As List lst.AddAll(Array As String("bingo","bongo","bango","bunga","bunga","figa")) Log(lst.Get(Rnd(0,lst.Size-1))) End Sub
link: Per rimanere al codice di @Star-Dust , qualcosa del genere dim mylist as list list.initialize list.addall(array as string("Giovanni","Mrco"...)) ....

","*","+","-",";","_") Dim charList As List charList.Initialize If numbers Then charList.AddAll(numbersArray) If lowercase Then charList.AddAll(lowercaseArray) If uppercase Then charList.AddAll(uppercaseArray) If symbols Then charList.AddAll(symbolsArray) Dim newP
link: ","*","+","-",";","_") Dim charList As List charList.Initialize If numbers Then charList.AddAll(numbersArray) If lowercase The
link: ","*","+","-",";","_") Dim charList As List charList.Initialize If numbers Then charList.AddAll(numbersArray) If lowercase The

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