W wheretheidivides Active Member Licensed User Longtime User Jan 6, 2013 #1 . Last edited: May 24, 2020
Cableguy Expert Licensed User Longtime User Jan 6, 2013 #2 Something like this... For a = 0 to edittext1.lenght-1 If stringat(edittext1.text,a) ="@" then its an e-mail Else if a = edittext1.lenght-1 then end of string, no e-mail Next This is just the concept, you have to come with the code yourself Upvote 0
Something like this... For a = 0 to edittext1.lenght-1 If stringat(edittext1.text,a) ="@" then its an e-mail Else if a = edittext1.lenght-1 then end of string, no e-mail Next This is just the concept, you have to come with the code yourself
T TedDog Member Licensed User Longtime User Jan 29, 2014 #3 I had valid email addresses get labeled as invalid using the regex code, so I just used Code: If EditText1.Contains("@") = True AND EditText1.Contains(".") = True Then <stuff> End If It won't flag illegal characters, but it won't generate false negatives either. Upvote 0
I had valid email addresses get labeled as invalid using the regex code, so I just used Code: If EditText1.Contains("@") = True AND EditText1.Contains(".") = True Then <stuff> End If It won't flag illegal characters, but it won't generate false negatives either.
DonManfred Expert Licensed User Longtime User Jan 29, 2014 #4 You can also use a masked EditText with this lib. As plus you find in the example regex-code which checks whether the input is valid (is an allowed eMail) or not. Informatix´s Libs rocks Upvote 0
You can also use a masked EditText with this lib. As plus you find in the example regex-code which checks whether the input is valid (is an allowed eMail) or not. Informatix´s Libs rocks
