Android Question Are the logical operators short-circuit?

Yes. They are converted to && and || in Java.

Of course, I should have realized that. Thanks a lot.

Yes. They are converted to && and || in Java.

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This is true. In release mode the operators are converted to && or ||. In debug mode they are converted to something different (which behaves the same but runs in the rapid engine).

The operators behavior are based on B4A language design not on the Java operators. The compiler could have easily generate different code if the language design was different.

Thanks Erel. To be honest: I don't really care what they are converted to since I'm really just interested in their behavior.

I must say that I'm really impressed by this tool. I bought a license after just watching some presentations on YouTube, I didn't even bother to download the trial first.