Mashiane Expert Licensed User Longtime User Mar 4, 2020 #1 Ola Here is some javascript... B4X: Return textOne.indexOf(searchText) > -1 || textTwo.indexOf(searchText) > -1 How can I write this the BANano way? Thanks
Ola Here is some javascript... B4X: Return textOne.indexOf(searchText) > -1 || textTwo.indexOf(searchText) > -1 How can I write this the BANano way? Thanks
alwaysbusy Expert Licensed User Longtime User Mar 4, 2020 #2 Like normal B4J I would think: B4X: Return textOne.indexOf(SearchText) > -1 Or textTwo.indexOf(SearchText) > -1 Upvote 0
Like normal B4J I would think: B4X: Return textOne.indexOf(SearchText) > -1 Or textTwo.indexOf(SearchText) > -1