I don't find solution to solve an error in this routine:
Sub Globals
Dim data(32768) As Byte, strings(102) As Byte, secret(0) As Byte, strbyte(0) As byte, temp(0) As Byte
Dim Buffer(4096) As byte, FotoR(100), URL, sum
Dim number(0) As int32
Dim Etot(8) As Byte
PassPhrase = "Passphrase numero uno 1 3243565476878878767"
PassPhrase2 = "Passphrase numero due 21 457889867684332423"
End Sub
Sub App_Start
Form1.show
End Sub
Sub Button1_Click
bit.New1
crypto.New1
secodes = "ed-4b-6f-39-e0-6e-4b-6d-b3-c-83-d4-ff-f7-80-59-bf-28-f2-a1-b7-ab-47-39-bd-42-3b-8a-a6-de-96-16-4a-3d-ee-4d-65-7e-31-e4-e2-66-2-1d-c0-c0-b4-8e-19-2a-2e-b7-bd-43-33-95-fe-e9-80-bb-c8-75-f1-5c-3e-a2-ba-80-52-64-6-d7-f5-10-95-9b-18-99-3c-12-f5-91-bd-de-ca-3a-78-37-37-84-5d-f5-d4-b1-3d-f2-9a-b2-5f-ea-20-eb-3b-76"
secret() = StrSplit(secodes,"-")
For i = 0 To ArrayLen(secret())-1
secret(i)=bit.HexToDec(secret(i))
Next
strings() = crypto.Decrypt(passphrase2,secret())
stringa = Bit.bytestostring(strings(),0,102)
The given back error is “crypto error” and comes in block letter given back in correspondence of the bold line.
Some idea? Thanks in advance…
Sub Globals
Dim data(32768) As Byte, strings(102) As Byte, secret(0) As Byte, strbyte(0) As byte, temp(0) As Byte
Dim Buffer(4096) As byte, FotoR(100), URL, sum
Dim number(0) As int32
Dim Etot(8) As Byte
PassPhrase = "Passphrase numero uno 1 3243565476878878767"
PassPhrase2 = "Passphrase numero due 21 457889867684332423"
End Sub
Sub App_Start
Form1.show
End Sub
Sub Button1_Click
bit.New1
crypto.New1
secodes = "ed-4b-6f-39-e0-6e-4b-6d-b3-c-83-d4-ff-f7-80-59-bf-28-f2-a1-b7-ab-47-39-bd-42-3b-8a-a6-de-96-16-4a-3d-ee-4d-65-7e-31-e4-e2-66-2-1d-c0-c0-b4-8e-19-2a-2e-b7-bd-43-33-95-fe-e9-80-bb-c8-75-f1-5c-3e-a2-ba-80-52-64-6-d7-f5-10-95-9b-18-99-3c-12-f5-91-bd-de-ca-3a-78-37-37-84-5d-f5-d4-b1-3d-f2-9a-b2-5f-ea-20-eb-3b-76"
secret() = StrSplit(secodes,"-")
For i = 0 To ArrayLen(secret())-1
secret(i)=bit.HexToDec(secret(i))
Next
strings() = crypto.Decrypt(passphrase2,secret())
stringa = Bit.bytestostring(strings(),0,102)
The given back error is “crypto error” and comes in block letter given back in correspondence of the bold line.
Some idea? Thanks in advance…