How do I cut string

[Shay]

I wish to remove only the left "0" in this string
(can't find how to do it)

a="0540123456"

thanks

 

[hdtvirl]

Look at the following

Shay, have a look at this tutorial from Erel,

regex

http://www.b4x.com/forum/basic4andr...3-regular-expressions-tutorial.html#post40844

You can use this fucntion to get the part of the stringyou want.

substring2 (Core) you will need to look at a tutorial on this also for full explaination of its use.


Regards

BOB

 

[boten]

if it is just the leftmost char then:

a=a.substring(1)

if you want the first occurance of "0" (wherever it is) then:

for i=0 to a.length-1
  if a.substring2(i,i+1)="0" then
     a=a.substring2(0,i) & a.substring(i+1)
     exit
 end if
next

 

[nfordbscndrd]

I wish to remove only the left "0" in this string
(can't find how to do it)

a="0540123456"

If you are familiar with VB syntax, you may want to look at the VB6-to-B4A guide in this post.

Also, this page in the Documentation Wiki (see the yellow link in the menu bar above) covers all String functions.

 

[pjd]

Here you go ...

a="540123456"


I'll get my coat.

 

[Kevin]

Here you go ...

a="540123456"


I'll get my coat.

Well, I was going to say "with a pair of scissors"......


(Sorry about that. His question was answered so I'm just having a bit of fun. I'm tired.)

 

[margret]

String Functions

Hello,

You can also try my function file that gives you a lot of functions to cut and change strings. It has sample code and functions like:

Right()
Left()
Mid()
Len()

To do what you are looking for would be:

YouVariable = Right("0540123456" , Len("0540123456") -1)

And a lot more. You can see and download here:

http://www.b4x.com/forum/basic4android-getting-started-tutorials/10365-string-functions.html

Thanks,

Margret

 

[Brad]

if you want the first occurance of "0" (wherever it is) then:

for i=0 to a.length-1
  if a.substring2(i,i+1)="0" then
     a=a.substring2(0,i) & a.substring(i+1)
     exit
 end if
next

Here's a simpler way to remove all occurrences of a character.

a = "08934060"
a = a.Replace("0","")
returns 89346