D Dey Active Member Licensed User Longtime User Mar 5, 2016 #1 B4A 5.8 Salve a tutti come mai questa funzione non va? dove sbaglio? Hello everyone why this function should not be? where am I wrong? B4X: Dim Pass2() As String Pass2=Regex.Split(".","1111.1963")
B4A 5.8 Salve a tutti come mai questa funzione non va? dove sbaglio? Hello everyone why this function should not be? where am I wrong? B4X: Dim Pass2() As String Pass2=Regex.Split(".","1111.1963")
DonManfred Expert Licensed User Longtime User Mar 5, 2016 #2 "." is a special char and need to be escaped. B4X: Dim Pass2() As String Pass2=Regex.Split("\.","1111.1963") Log("PassSize="&Pass2.Length) For i = 0 To Pass2.Length-1 Log($"Pass ${Pass2(i)}"$) Next
"." is a special char and need to be escaped. B4X: Dim Pass2() As String Pass2=Regex.Split("\.","1111.1963") Log("PassSize="&Pass2.Length) For i = 0 To Pass2.Length-1 Log($"Pass ${Pass2(i)}"$) Next
D Dey Active Member Licensed User Longtime User Mar 5, 2016 #3 DonManfred said: "." is a special char and need to be escaped. B4X: Dim Pass2() As String Pass2=Regex.Split("\.","1111.1963") Log("PassSize="&Pass2.Length) For i = 0 To Pass2.Length-1 Log($"Pass ${Pass2(i)}"$) Next Click to expand... thanks solved
DonManfred said: "." is a special char and need to be escaped. B4X: Dim Pass2() As String Pass2=Regex.Split("\.","1111.1963") Log("PassSize="&Pass2.Length) For i = 0 To Pass2.Length-1 Log($"Pass ${Pass2(i)}"$) Next Click to expand... thanks solved