Android Question [SOLVED] TcpIp ServerSocket wan't receive data from Windows

[Lello1964]

I have an android server service that uses ServerSocket, it receives data using the TCP-ip protocol.

If I connect from an App made with B4A and send the data, it works perfectly.

If I try to send data from Windows using mswinsocket or from a non-B4A andorid App, it gives me the connection but does not receive the data.

??

 

[DonManfred]

??

Absolutely right...

??

How should one help? You are NOT PROVIDING a b4x code, not providing any non b4x code.
The only thing we can do is guessing

Best would be if you provide a testproject (b4a and windowsapp which sends data. Best with source. I don´t see how we could help otherwise ;-)

 

[Lello1964]

Sorry,

Server use :

Sub Process_Globals
    Public server As ServerSocket
    Private client As Socket
    Private AstreamPagamico As AsyncStreams
.......

Private Sub ListenForConnections
    Log("Chiamata TCPip")
    Do While working
        server.Listen
        Wait For server_NewConnection (Successful As Boolean, NewSocket As Socket)
     
        If Successful Then
            CallSub(Main, "SetState")
            client = NewSocket
            Astream.InitializePrefix(client.InputStream, False, client.OutputStream, "Astream")

..................

Client :

using MsWindowsSocket

.
thisform.tcpIP.object.Protocol=0


thisform.tcpIP.object.RemotePort=2100
thisform.tcpIP.object.connect("192.168.1.162",2100)

MessageBox(THISFORM.TCPIP.OBJECT.STate)

If Thisform.TCPIP.STate < 7
Messagebox("chiudo")
Thisform.TCPIP.Object.Close()
Cancel
Exit

Endif

Thisform.TCPIP.OBJECT.SendData( "aa" )

I 've also tryed to send data using Tcp-Ip Client from PlayStore.

If i receive from Wiindows Sever, i wil receive data from allk.

But using B4a Server, from B4A client receive data, but from Windows and non B4A Android app connection ok, but no data received.

I don't know why ?

I'm trying from yesterday but no solution.

 

[Lello1964]

Thanks to @Star-Dust

Astream.InitializePrefix(client.InputStream, False, client.OutputStream, "Astream")

instead of

Astream.Initialize(client.InputStream, client.OutputStream, "Astream")