string split function

[gjoisa]

I can't find string split function . How to get it ? for eg:

dim temp as string
dim rst() as string
temp = "Ravi,Hari,Raman,Anitha,Vinod"
rst = Split(temp,",")

Actually array variable rst shoud get splitted strings from temp .
P.S: Last line in code does not work .

 

[Merlot2309]

Hi,

Regex should do it, see: Basic4android - Regular Expressions (Core)

Success,
Helen.

 

[Theera]

I can't find string split function . How to get it ? for eg:

dim temp as string
dim rst() as string
temp = "Ravi,Hari,Raman,Anitha,Vinod"
rst = Split(temp,",")

Actually array variable rst shoud get splitted strings from temp .
P.S: Last line in code does not work .

Example:
Dim components() As String
components = Regex.Split(",","abc,def,,ghi") 'returns: "abc", "def", "", "ghi"

components(0)="abc"
components(1)="def"
components(2)=""
components(3)="ghi"

 

[cbal03]

Split appears to behave incorrectly

Dim strVersion As String
Dim lstVersions As List


strVersion = "1,0,0a"
lstVersions = Regex.Split(",",strVersion) 'list items seperated by comma.
Log("Split version: " & strVersion) 'show original string
Log(lstVersions) 'show list contents

output:
(ArrayList) [1, 0, 0a]

The above works fine. However when I use a dot for the seperating text the list isn't filled. Like below.


Dim strVersion As String
Dim lstVersions As List


strVersion = "1.0.0a"
lstVersions = Regex.Split(".",strVersion) 'list items seperated by dot.
Log("Split version: " & strVersion) 'show original string
Log(lstVersions) 'show list contents - LIST IS EMPTY?

output:
(ArrayList) []


Thanks in advance!

 

[klaus]

You must use:

lstVersions = Regex.Split("\.",strVersion)

beccause the dot is a special character in Regex.

Best regards.

 

[cbal03]

Thanks Klaus! It works.