Is it possible use HttpUtils2 to upload file?

[sally3599]

HttpUtils2 can post data, can it upload a big file?

 

[Erel]

You can add it as a GET parameter:

job2.PostFile("http://ccotesting.site11.com/serTestUpload.php?FileName=file.zip", File.DirInternal, varZipFileUp)

You will need to use StringUtils.EncodeUrl to encode the file name (if it has spaces or other non-ASCII characters).

 

[mc73]

I think in the past I dealt with this by sending the fileName and the fileContent splitted by a "//" separator, then exploded the content in an array to set the file name.

 

[mc73]

You can add it as a GET parameter:

job2.PostFile("http://ccotesting.site11.com/serTestUpload.php?FileName=file.zip", File.DirInternal, varZipFileUp)

You will need to use StringUtils.EncodeUrl to encode the file name (if it has spaces or other non-ASCII characters).

This was a choice I used, but then decided to turn it off. I am always afraid of GET variables, in such operations

 

[Erel]

The POST payload is not more secure than the GET parameters. Especially when both are sent from an app and not seen in the browser.

 

[mc73]

The POST payload is not more secure than the GET parameters. Especially when both are sent from an app and not seen in the browser.

There is a tiny difference in my opinion. If one has the link, she can experiment with the GET parameter. But anyway, I am not that concerned with the security problem. I am more concerned with accidental bad inputs with gets when a user uses a link outside of an app. This happened every day in a intranet app of mine

 

[Erel]

If one has the link, she can experiment with the GET parameter.

This is only relevant when the link is in the browser. Not inside the app.

 

[unba1300]

What is the syntax when passing more than one variable using this approach? When I try

job2.PostFile("http://ccotesting.site11.com/serTestUpload.php?FileName="&varZipFileUp&"Age="&i&"theSize="&varZipFileUpSize, File.DirInternal, varZipFileUp)

it assigns all three variables to FileName. Thanks.

 

[mc73]

You should add & inside the quotes as well.

"your.php?var1=" & yourVar1 & "&var2=" & yourVar2

and so on...

 

[Erel]

I recommend you to call StringUtils.EncodeUrl for each of the parameters. Will save you a few bug reports...

 

[DonManfred]

@unum4848

 $FileName = $_GET['FileName'];

is not equal to

 $PostData = file_get_contents("php://input");

To write the file to your upload directory you have to write the contents of $PostData to a file.

$PostData = file_get_contents("php://input");
file_put_contents('/path/to/uploaddir/upload.zip', $PostData);

I didn´t worked with php://input in all the years... So i did not really know what $PostData do have as Content.
php-doku says it uses less memory than using $HTTP_RAW_POST_DATA.

I suggest debugging the contents of $_POST after uploading and getting the $PostData. Write a log and have a look at this log after uploading a file...
Remember that the log should be writte to a path where the script can write (chmod 777 or 644)

$file_handle = fopen('./b4a_'.date("Y-W", time()).'.log', 'a+');
fwrite($file_handle, "======== POST-Data (RAW)====================="."\r\n");
fwrite($file_handle, "PostData = ".$PostData."\r\n");
fwrite($file_handle, "======== POST-Data ========================="."\r\n");
foreach($_POST as $name => $value){
  fwrite($file_handle, date("d.m.Y H:i:s", time()).": ".$name."=".$value." ".$add."\r\n");
}
fwrite($file_handle, "======== GET-Data ========================="."\r\n");
foreach($_GET as $name => $value){
  fwrite($file_handle, date("d.m.Y H:i:s", time()).": ".$name."=".$value." ".$add."\r\n");
}
fwrite($file_handle, "======================================"."\r\n");
fclose($file_handle);

 

[rossati]

Hello

I apologize but I am not able to upload a file, i.e. the JobDone event is not fired.
Where is my fauult?
hera the (simple code) whit some try, insertString and Download2, which works:

    sendImg.Initialize("sendImgJob", Me)  
    sendImg.PostFile("http://rete.condorinformatique.com/upload.php?fileName=image.jpg",dir, fileName)
'    sendImg.PostString("http://rete.condorinformatique.com/upload.php", "&key2=value2&fileName=image.jpg")
'    sendImg.Download2("http://rete.condorinformatique.com/upload.php", _
'      Array As String("first key", "first value :)", "second key", "value 2"))
Sub JobDone (Job As HttpJob)
  ToastMessageShow("Done ", True)
  Log("JobName = " & Job.JobName & ", Success = " & Job.Success)
  Job.Release
End Sub

best regards

John Rossati

 

[Erel]

I've just tried this code and JobDone is raised:

Sub Activity_Create(FirstTime As Boolean)
   Dim sendimg As HttpJob
   sendimg.Initialize("sendImgJob", Me)  
  sendimg.PostFile("http://rete.condorinformatique.com/upload.php?fileName=image.jpg", File.DirRootExternal, "1.xls")
End Sub
Sub JobDone (Job As HttpJob)
  Log("JobName = " & Job.JobName & ", Success = " & Job.Success)
  Job.Release
End Sub

 

[rossati]

Thanks
I have tried your script and my be one times worked, this get a strange answer:

Sub Activity_Create(FirstTime As Boolean)
  Dim sendimg As HttpJob
  sendimg.Initialize("sendImgJob", Me) 
  sendimg.PostFile("http://rete.condorinformatique.com/upload.php?fileName=xximage.jpg", File.DirRootExternal, "image.jpg")
  sendimg.PostString("http://rete.condorinformatique.com/upload.php", "&key3=value2&fileName=image.jpg")
End Sub
Sub JobDone (Job As HttpJob)
  Log("JobName = " & Job.JobName & ", Success = " & Job.Success)
  Log(Job.GetString)
  Job.Release
End Sub

The answer is:

** Activity (main) Create, isFirst = true **
** Activity (main) Resume **
** Service (httputils2service) Create **
** Service (httputils2service) Start **
** Service (httputils2service) Start **
JobName = sendImgJob, Success = true
2047056561<pre>Array
(
)
Array
(
  [key3] => value2
  [fileName] => image.jpg
)
JobName = sendImgJob, Success = true

2132198191<pre>Array
(
)
Array
(
  [key3] => value2
  [fileName] => image.jpg
)
** Activity (main) Pause, UserClosed = false **

It seems two different instance of sendstring, here the PHP:

<?PHP
echo rand()."<pre>";print_r($_FILES);
print_r($_REQUEST);
if (isset($_FILES['fileUpload']['name'])) {
    $flName = $_FILES['fileUpload']['name'];
    move_uploaded_file($_FILES['fileUpload']['tmp_name'],$flName );
}
?>

Timing problems? Android Samsung Version?

best regards

John Rossati

 

[DonManfred]

you should just use one of thesenot both

 sendimg.PostFile("http://rete.condorinformatique.com/upload.php?fileName=xximage.jpg", File.DirRootExternal, "image.jpg")
  sendimg.PostString("http://rete.condorinformatique.com/upload.php", "&key3=value2&fileName=image.jpg")

 

[rossati]

thanks Manfred

this is a try, I have no answer if I use sendimg.PostFile and also if I invert the two instructions

regards John

 

[DonManfred]

See 1st link in my signature for an -working - example

 

[rossati]

Thanks Manfred

I apologize the time I have stealed to all, the probleme seem to be on my provider, I am asking confirm.
best regards

John

 

[EvgenyB4A]

Hi
I have the problem with post file that should be uploaded to ASP.NET page:

Dim job1 As HttpJob

job1.Initialize(
"Job1", Me)

'job1.PostFile(
"http://192.168.10.202/UniVend-Terminal/upload.aspx",File.DirRootExternal,"Cash00000027.txt")

The server gets the request but do not see any files.
At JobDone sub I get success.
When I send files from Windows PC application to the same page, the server sees the files.

What is wrong?

 

[Erel]

Job.PostFile sends a POST request with the file content as the POST payload. Which format is expected by your server?

 

[EvgenyB4A]

Job.PostFile sends a POST request with the file content as the POST payload. Which format is expected by your server?

Do you mean "GET" or "POST"? My server expects POST.