mrossen Active Member Licensed User Longtime User Oct 1, 2012 #1 Hi, Anyone know a smart way to find the first available number in at array like this : [1, 2, 3, 5, 6, 7]. I would like to get the result 4 or [1,2,3,4] the result will be 5 or [2,3,4,5] the result will be 1 Mogens
Hi, Anyone know a smart way to find the first available number in at array like this : [1, 2, 3, 5, 6, 7]. I would like to get the result 4 or [1,2,3,4] the result will be 5 or [2,3,4,5] the result will be 1 Mogens
mc73 Well-Known Member Licensed User Longtime User Oct 1, 2012 #2 Code: dim ar() as int ar(0)=1:ar(1)=2:ar(2)=3:ar(3)=5:ar(4)=6:ar(5)=7 n=ar.size dim s1,s2 as int s1=(n+1)*(n+2)/2 s2=0 for k=0 to n-1 s2=s2+ar(k) next msgbox(s1-s2,"you mean this?") Upvote 0
Code: dim ar() as int ar(0)=1:ar(1)=2:ar(2)=3:ar(3)=5:ar(4)=6:ar(5)=7 n=ar.size dim s1,s2 as int s1=(n+1)*(n+2)/2 s2=0 for k=0 to n-1 s2=s2+ar(k) next msgbox(s1-s2,"you mean this?")
