Android Question Replace character at position X

[wonder]

Maybe I'm missing something...

Let's say I have a random string.

Dim str = "asdasdhjkahdkjahdkjashd" As String

I want to replace the 5th character with "0".

str.CharAt(4) = "0" doesn't work...

str.Replace(CharAt(4), "0") wouldn't work either, as it would replace every "s".

 

[MikeH]

str = str.substring2(0,3) & newChar & str.substring(5)

 

[wonder]

Aha!! Thanks Mike!

...but isn't there a more elegant way to do it?

 

[RandomCoder]

I was just about to reply with the same as @MikeH although I think that the 3 should really be a 4.
CharAt is a read-only method.

 

[wonder]

Sometimes I kinda miss *char pointers...

 

[MikeH]

I was just about to reply with the same as @MikeH although I think that the 3 should really be a 4.
CharAt is a read-only method.

Yes, its late and Im tired after a solid day of coding. I edited those numbers at least twice

 

[wonder]

We need a .ReplaceAt()

 

[Erel]

Strings are immutable. You cannot replace a character. You can create a new string based on the previous one:

Dim s As String = "abcdef"
s = StrReplaceAt(s, 2, "X")

Sub StrReplaceAt(str As String, Index As Int, Replacement As String) As String
   Dim newStr As String = str.SubString2(0, Index) & Replacement
   If Index < str.Length - 1 Then newStr = newStr & str.SubString(Index + 1)
   Return newStr
End Sub

 

[wonder]

Thanks!! I was going to write it myself, but you got there faster!