Android Question [SOLVED] Translate code to MatrixOp

[scsjc]

They have given me this code in which they tell me that I can correct a prospective projection. Obtaining the X and Y vectors of the projection in their corrected position.
But I don't know very well how to run it within B4A, and I see some clues with the MatrixOP library but I don't know if it can be done, and what I am doing is correct.
I would appreciate any help. Thanks.

    'distorted reference points
    Dim xd(5) As Int
    xd(1) = 0
    xd(2) = 1000
    xd(3) = 1000
    xd(4) = 0
    Dim yd(5) As Int
    yd(1) = 0
    yd(2) = 0
    yd(3) = 600
    yd(4) = 600
    'unidistorted points
    Dim xu(5) As Int
    xu(1) = 1600+200
    xu(2) = 1600+200
    xu(3) = 1000+200
    xu(4) = 1000+200
    Dim yu(5) As Int
    yu(1) = 0
    yu(2) = 1000
    yu(3) = 1000
    yu(4) = 0
    'solve 8 equaciones lineales syste : A * k = b -> k = inv(A) * b
    Dim Amatriz(8,8) As Double
    Dim valoresfila1() As Int = Array As Int(    xd(1),    yd(1),     1,    0,        0,         0,     (xd(1)*-1)*xu(1),     (yd(1)*-1)*xu(1) )
    For columna=0 To 7
        Amatriz(0, columna) = valoresfila1(columna)
    Next
    Dim valoresfila1() As Int = Array As Int(    0,        0,         0,     xd(1),    yd(1),     1,     (xd(1)*-1)*yu(1),     (yd(1)*-1)*yu(1) )
    For columna=0 To 7
        Amatriz(1, columna) = valoresfila1(columna)
    Next
    Dim valoresfila1() As Int = Array As Int(    xd(2),     yd(2),    1,    0,        0,        0,    (xd(2)*-1)*xu(2),    (yd(2)*-1)*xu(2) )
    For columna=0 To 7
        Amatriz(2, columna) = valoresfila1(columna)
    Next
    Dim valoresfila1() As Int = Array As Int(    0,        0,        0,    xd(2),    yd(2),     1,    (xd(2)*-1)*yu(2),    (yd(2)*-1)*yu(2) )
    For columna=0 To 7
        Amatriz(3, columna) = valoresfila1(columna)
    Next
    Dim valoresfila1() As Int = Array As Int(    xd(3),    yd(3),    1,    0,        0,        0,    (xd(3)*-1)*xu(3),    (yd(3)*-1)*xu(3) )
    For columna=0 To 7
        Amatriz(4, columna) = valoresfila1(columna)
    Next
    Dim valoresfila1() As Int = Array As Int(    0,        0,        0,    xd(3),    yd(3),    1,    (xd(3)*-1)*yu(3),    (yd(3)*-1)*yu(3) )
    For columna=0 To 7
        Amatriz(5, columna) = valoresfila1(columna)
    Next
    Dim valoresfila1() As Int = Array As Int(    xd(4),    yd(4),    1,    0,        0,        0,    (xd(4)*-1)*xu(4),    (yd(4)*-1)*xu(4) )
    For columna=0 To 7
        Amatriz(6, columna) = valoresfila1(columna)
    Next
    Dim valoresfila1() As Int = Array As Int(    0,        0,        0,    xd(4),    yd(4),    1,    (xd(4)*-1)*yu(4),    (yd(4)*-1)*yu(4) )
    For columna=0 To 7
        Amatriz(7, columna) = valoresfila1(columna)
    Next
    Dim b() As Double
    b = Array As Double(    xu(1),    yu(1),    xu(2),    yu(2),    xu(3),    yu(3),    xu(4),    yu(4)    )
    
    Dim matr As MatrixOp
    Dim k As Double
    k = matr.SolveV(8,Amatriz,b, XXXXXXXXXXX )

 

[Brian Dean]

You might have sorted this out for yourself by now, but this is the code that I think you should be using . . .

    Dim k(8) As Double
    matr.SolveV(8, Amatriz, b, k)
    For i = 0 To 7
        Log(k(i))
    Next

The result that I got was this . . .

0
-1
1800
1
0
0
0
0

I have no idea if it is correct - it doesn't feel right to me - but you might have errors elsewhere.

 

[scsjc]

You might have sorted this out for yourself by now, but this is the code that I think you should be using . . .

    Dim k(8) As Double
    matr.SolveV(8, Amatriz, b, k)
    For i = 0 To 7
        Log(k(i))
    Next

The result that I got was this . . .

0
-1
1800
1
0
0
0
0

I have no idea if it is correct - it doesn't feel right to me - but you might have errors elsewhere.

yes work perfectly, thanks