Android Question Rounding down

[nibbo]

Simple I am sure but I can't find it in the documentation.
How do I round down to 2 decimal places?

 

[sorex]

use round2(x,2)

 

[wonder]

use floor()

Floor indeed, but it truncates the decimal places. Here's the code snippet that you need:

Sub RoundDown(number As Double, decimalPlaces As Int) As Double  
    Return Floor(number * Power(10, decimalPlaces)) / Power(10, decimalPlaces)
End Sub

Corrected version, thanks Sorex.

Log(RoundDown(24.1499999)) 'Output: 24.14

 

[sorex]

Floor indeed, but it truncates the decimal places.

yeah, I corrected it immediatly after my post tho

 

[sorex]

but it rounds up so it ain't good for him

 

[wonder]

yeah, I corrected it immediatly after my post tho

Ahh, I see you corrected it. Round2 will however always round up. 24.1499 will become 24.15.

 

[sorex]

Dim i As Double
i=2.34999
Log( Floor(i*100)/100 )

not sure if it's safe for all values tho

 

[sorex]

by the way do you sometimes need to look for your cursor with that theme? I use it too at home and sometimes the cursor is kind of lost in the background.

 

[wonder]

Dim i As Double
i=2.34999
Log( Floor(i*100)/100 )

not sure if it's safe for all values tho

Ahaha good job!! I think I like math a little bit too much! You solution is way simpler than mine!

EDIT: No... No issues with the cursor.

 

[nibbo]

Thanks all, yes I found Floor truncates the decimals and returns an integer even though the when you type Floor it implies it will return a double.
As stated above Round2 always rounds up.
I will write a little function using the Floor(double * 100) / 100 which seems the neatest.
Thanks all.