Android Question Server-Client-how can I get the real name of the file?

[XorAndOr]

hello, the server works fine, it receives the files. Only the names are not the real names of the file.

018-05-15 11:20:37.838:INFO::main: Logging initialized @378ms to 
2018-05-15 11:20:38.689:INFO:oejs.Server:main: Started @1232ms
Server started
Received file: image%3A8321.png, size=11801
Received file: image%3A8320.png, size=10691
Received file: image%3A8319.png, size=9574
Received file: image%3A8322.png, size=9826
Received file: image%3A8316.png, size=35600

Sub Button1_Click
    cc.Initialize("CC")
    cc.Show("image/*","Choose image")
End Sub

Sub cc_Result (Success As Boolean, Dir As String, FileName As String)   

    If Success = True Then
        
        Dim out As OutputStream
        out.InitializeToBytesArray(0)
        Dim In As InputStream = File.OpenInput(Dir, FileName)
        File.Copy2(In, out)
    
        Dim lastSlash As Int = FileName.LastIndexOf("/")
        If lastSlash > -1 Then
            FileName = FileName.SubString(lastSlash + 1)
        End If
        Dim su As StringUtils
        Dim j As HttpJob
        j.Initialize("file", Me)
        j.PostBytes(link & "?type=file&name=" & su.EncodeUrl(FileName & ".png", "UTF8"), out.ToBytesArray)

        Log(FileName)                       
        
                
    End If
    
    
End Sub

I tried the solution of the link below

https://www.b4x.com/android/forum/t...s-returned-from-contentchooser.39313/#content

but the names are always with image% 3A8316 ... etc ... I'm missing something?

thanks

 

[OliverA]

You are URL encoding the filename on the client side. Are you URL decoding the filename on the server side?

 

[Erel]

What is the output of Log(FileName) on the client?

 

[XorAndOr]

What is the output of Log(FileName) on the client?

thanks for help
the log after If Succes = True Then

content://com.android.providers.media.documents/document/image%3A8321

the log after j.PostBytes(link,........)

image%3A8321

 

[Erel]

The issue has nothing to do with the server or the communication.

It is a mistake to assume that you can get a meaningful file name from the URI returned from ContentChooser.

In this specific case you can use StringUtils.DecodeUrl to convert it to image:8321.