K KPmaster Member Licensed User Longtime User Oct 27, 2014 #1 Hi all, I'm trying to understand how to manage the authentication to a video stream I'm accessing to using Videomjpeg library, but I didn't find a solution to my case. The stream can be accessed via url using the classic syntax: http://user:pass@ip Unfortunatelly, username and password aren't parameters of the url command-line so I cannot add them to it. How can I pass them to the Videomjpeg library? In my code, I use this: Code: Dim cam1 As Videomjpeg cam1.cam("192.168.1.100",80,"/control/faststream.jpg?stream=MxPEG") This way, the app freeze. I've tried to put the url syntax in the first parameter (without the "http://" at the begin), but it didn't work.
Hi all, I'm trying to understand how to manage the authentication to a video stream I'm accessing to using Videomjpeg library, but I didn't find a solution to my case. The stream can be accessed via url using the classic syntax: http://user:pass@ip Unfortunatelly, username and password aren't parameters of the url command-line so I cannot add them to it. How can I pass them to the Videomjpeg library? In my code, I use this: Code: Dim cam1 As Videomjpeg cam1.cam("192.168.1.100",80,"/control/faststream.jpg?stream=MxPEG") This way, the app freeze. I've tried to put the url syntax in the first parameter (without the "http://" at the begin), but it didn't work.
