Android Question why #if Release doesn't work

[alimanam3386]

Hi , I have bellow code in a module :

Public Sub GetShareLink As String
  #if GOOGLE
      Return "https://play.google.com/store/apps/details?id=..."
  #Else
      Return "https://cafebazaar.ir/app/..."
  #End If
End Sub

also in Build Configurations I defined two configuration ( GOOGLE AND OTHER ) but when I try to call this sub ( GetShareLink ) always I get same result ( "https://cafebazaar.ir/app/..." ) even when I change the build configuration to OTHER OR GOOGLE I get same result , why ?

 

[angel_]

Try this:

Public Sub GetShareLink As String
  #if GOOGLE
      Return "https://play.google.com/store/apps/details?id=..."
  #Else if NOT(GOOGLE)
      Return "https://cafebazaar.ir/app/..."
  #End If
End Sub

 

[alimanam3386]

Try this:

Public Sub GetShareLink As String
  #if GOOGLE
      Return "https://play.google.com/store/apps/details?id=..."
  #Else if NOT(GOOGLE)
      Return "https://cafebazaar.ir/app/..."
  #End If
End Sub

Not difference

 

[angel_]

How do you have build configurations?

 

[alimanam3386]

I forgot to add conditional symbols . Now it works. thank you

 

[alimanam3386]

I confused It worked once but now I still have problem with that again!

 

[angel_]

Check the attachment

 

[alimanam3386]

Check the attachment

works nice thanks , so we should not separate the conditional symbols with comma for any build configuration right ?

 

[angel_]

works nice thanks , so we should not separate the conditional symbols with comma for any build configuration right ?

No, por example if you want this

    #If NO_ADS
        #if GOOGLE
            Return "https://play.google.com/store/apps/details?id=com.porshesoft.oneaye"
        #Else
            Return "https://cafebazaar.ir/app/com.porshesoft.oneaye"
        #End If
    #Else
        Return "https://..."
    #End If

GOOGLE: GOOGLE, NO_ADS
CAFEBAZAAR: CAFEBAZAAR, NO_ADS