Android Question width = width*(pct*(width>height)) ... Possible?

[Marc De Loose]

I would like to write:
width = width*(pct*(width>height))

what would resolve to:
(if width is greater than height)
width = width*(pct*1)

if not
width = width *(pct*0)

is width = width*(pct*(width>height)) somehow possible?

 

[LucaMs]

No, your code can not work.

I would use:

Public Sub IIF(c As Boolean, TrueRes As Object, FalseRes As Object) As Object
   If c Then Return TrueRes Else Return FalseRes
End Sub

width = width * pct * IIF(width > height, 1, 0)

 

[MarkusR]

or make this boolean a number

Sub Test

    Dim width,height,pct As Float
    width = 200
    height  =100
    pct = 5
    
    width = width*(pct*B(width>height))

    Log(width)

End Sub

Sub B(truefalse As Boolean) As Float
    
    If truefalse Then Return 1.0 Else Return 0.0
        
End Sub

 

[Brandsum]

is width = width*(pct*(width>height)) somehow possible?

Yup that's quite easy!!

width = width * (pct * Min(1,Max(width-height,0)) )

 

[LucaMs]

Note that IIF is a useful function to be reused; otherwise it was worth using a full "if" block.

 

[emexes]

I would like to write:
width = width*(pct*(width>height))

what would resolve to:
(if width is greater than height)
width = width*(pct*1)

if not
width = width *(pct*0)

I'd be inclined to just go with:

if width > height then
    width = width * pct
else
    width = 0
end if

which I feel wins on simplicity, efficiency and brevity, but if you must have it as one statement (if we ignore the called function...) then LucaMs wins:

width = IIF(width > height, width * pct, 0)

with Brandsum in a close but cryptic second place, assuming width and height are integers ;-)

 

[Brandsum]

Note that IIF is a useful function to be reused; otherwise it was worth using a full "if" block.

That's true. But I just tried to give a minimal solution for what he wanted width = width*(pct*(width>height))