B4J Question wrong formatting applied with math in advanced strings?

sorex

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Hello,

It seems that the "no formatting" method is being overruled when math is being applied in the advanced strings method.

I noticed it when removing recalculated grid coordinates from a map didn't seem to work.

B4X:
Log($"d0=${data2(0)} - d1:${data2(1)} - sy:${sy} - sx=${sx} dy=${data2(0)-sy} - dx:${data2(1)-sx}"$)

Log($"d0=$1.0{data2(0)} - d1:$1.0{data2(1)} - sy:$1.0{sy} - sx=$1.0{sx} dy=$1.0{data2(0)-sy} - dx:$1.0{data2(1)-sx}"$)

log:

d0=4 - d1:4 - sy:4 - sx=4 dy=0.0 - dx:0.0
d0=4 - d1:4 - sy:4 - sx=4 dy=0 - dx:0

notice the 0.0 on the substracted values
 

sorex

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the numbers are plain INTs. there's no need to add .0 to it as I didn't pick $1.1{} so the assumed format is just 1.0 as I use ${} (no formatting).
 
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sorex

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see it as abs(0-1) would still give -1. the outer command is ignored (not removing the 0.0 formatting)
 
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sorex

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sorry but I don't see the relevance as the ${} no format happends last in the "operation"

I select no formatting and there is formatting applied. it should only be there when it is for example 0.5

no formatting means to me removing formatting if there is any on INTs and not adding some unwanted one.
 
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Erel

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BTW, the output of this code is 0 not 0.0:
B4X:
Dim sx, sy As Int
Dim data2(10) As Int
Log($"d0=${data2(0)} - d1:${data2(1)} - sy:${sy} - sx=${sx} dy=${data2(0)-sy} - dx:${data2(1)-sx}"$)
Still it is a programming mistake to omit the formatting specification as the default formatting might not be what you expect. It is also very simple to do.
 
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sorex

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data2() is strings because data comes from a regex.split

that there are differences between the old fashioned method and the advanced one can be seen with this code and only the ${} method adds formatting.
putting the blame on a coding mistake would make the old fashioned method format wrong aswell but it doesn't as it covers something that is missing in ${}.
both method should output the same thing that's what I'm trying to say.

B4X:
Dim v1 As String=2
Dim v2 As Int=1
Log(v1-v2)
Log("v:"& (v1-v2))
Log($"v:${v1-v2}"$)

Waiting for debugger to connect...
Program started.
1
v:1
v:1.0
 
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Erel

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Moved to the questions forum.

data2() is strings because data comes from a regex.split
When a string is parsed to a number it can be converted to a double. You shouldn't assume that it will be converted to an int just because the number is a whole number.

Bottom line, which was written 5 times already, use the format specifier. It is very simple.
 
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