Android Question xmlsax help

[tufanv]

Hello

I was checking out Erel's xmlsax tutorial and tried it on my xml. But my xml style is totally different so i dont know how to get a value for a specific date. this is the xml link:

http://www.namazvakti.com/XML2016/16/16742.xml

i copied it to files folder and parsed it with xmlsax. Erel's tutorial's xml seems different to me ( I dont have any experience in xml files so i dont know if it is different or not)

It would be nice if some one can point me to right direction for geting the times for dayofyear 30 for example.

  <prayertimes dayofyear="30" day="30" month="1">5:32    5:48    7:12    8:02    12:14    12:35    15:20    16:02    16:57    17:38    18:30    19:07    19:18    10:08    a    b    </prayertimes>

there are 12 different times for different purposes. Lets say i want to get the 4th on that is 8:02

Thanks for your help in advance.

 

[Erel]

There is a single XML text element here. It starts with 5:32 and ends with "a b ".
You will need to use XmlSax to get the text element (should be simple) and then split it with Regex.Split. Use \s as the separator.

 

[tufanv]

There is a single XML text element here. It starts with 5:32 and ends with "a b ".
You will need to use XmlSax to get the text element (should be simple) and then split it with Regex.Split. Use \s as the separator.

But i have selected the line manually and copied here. I must make the app select todays date inside the xml for example here i selected the 30th of january. If today is 19th september how can i get the actua line from xml ?

if i can select the correct line than i can do as you say splitting with regex

 

[Erel]

You need to handle the StartElement event and check the attributes. Once you find the correct one, set a global variable and then read the text in EndElement event.