C calabozo2006 Member Aug 24, 2022 #1 Hello people My question is the following, in text messages (SMS), carriage returns are included, I'm trying to intercept the CHR(13) but I can't, what's more, it's not in the message, does anyone have an opinion on regard. Greetings.
Hello people My question is the following, in text messages (SMS), carriage returns are included, I'm trying to intercept the CHR(13) but I can't, what's more, it's not in the message, does anyone have an opinion on regard. Greetings.
DonManfred Expert Licensed User Longtime User Aug 24, 2022 #2 Try to replace CHR(13) and CHR(10). Upvote 0
C calabozo2006 Member Aug 25, 2022 #3 Perhaps I did not express myself well, I do not detect the CHR(13) in the text of the SMS, I analyze character by character and it is not there. Greetings. Upvote 0
Perhaps I did not express myself well, I do not detect the CHR(13) in the text of the SMS, I analyze character by character and it is not there. Greetings.
P PaulMeuris Well-Known Member Licensed User Aug 25, 2022 #4 calabozo2006 said: I'm trying to intercept the CHR(13) but I can't, what's more, it's not in the message Click to expand... Where are the carriage returns then? Upvote 0
calabozo2006 said: I'm trying to intercept the CHR(13) but I can't, what's more, it's not in the message Click to expand... Where are the carriage returns then?
C calabozo2006 Member Aug 25, 2022 #5 PaulMeuris said: Where are the carriage returns then? Click to expand... If I use the Log to see the data, it appears like this: Log(D1) : Pedro 25 years 1.75 meters but when it looks for the CHR(13) or the CHR(10), I don't find it parsed character by character... Upvote 0
PaulMeuris said: Where are the carriage returns then? Click to expand... If I use the Log to see the data, it appears like this: Log(D1) : Pedro 25 years 1.75 meters but when it looks for the CHR(13) or the CHR(10), I don't find it parsed character by character...
Sandman Expert Licensed User Longtime User Aug 25, 2022 #6 This is very simple to figure out by yourself. Iterate through a message and log each character, together with the ASCII value. Should give you all the info you need in a couple of minutes. Upvote 0
This is very simple to figure out by yourself. Iterate through a message and log each character, together with the ASCII value. Should give you all the info you need in a couple of minutes.
Erel B4X founder Staff member Licensed User Longtime User Aug 25, 2022 #7 Code: Copy Dim s As String For i = 0 To s.Length - 1 Log(Asc(s.CharAt(i))) Next Upvote 0