Android Question random label

[Douglas Farias]

how can i put a label random position on my screen

for exemple when start the app show

10% top 10% left

or 20% top
etc
random
its possible?

 

[NJDude]

Yes it is possible, have you tried?

 

[Douglas Farias]

with Label1.Left = caca&"%y" xD
CACA is a random rnd(0,99) result

and this dont work
Rnd(0,99)%y

 

[NJDude]

You cannot do VarName & "%" but you are on the right path.

 

[Douglas Farias]

if help someone

Dim lado,alto As Int
lado = GetDeviceLayoutValues.Width
alto = GetDeviceLayoutValues.Height
r1 = Rnd(0,lado)
r2 = Rnd(0,alto)

    Label1.Left = r1
    Label1.top = r2

 

[stevel05]

Just limit the width and height so the label doesn't disappear off the screen:

r1 = Rnd(0,lado - Label1.Width)
r2 = Rnd(0,alto - Label1.Height)

 

[Douglas Farias]

xD
when I went to post you posted first
thx man

i see this problem because i have my label out of screen

 

[NJDude]

Or you could limit the area too, check the attached sample.

 

[NJDude]

Just limit the width and height so the label doesn't disappear off the screen:

r1 = Rnd(0,lado - Label1.Width)
r2 = Rnd(0,alto - Label1.Height)

The label will disappear or look incomplete in case the number is zero.

 

[stevel05]

The label will disappear or look incomplete in case the number is zero.

0,0 is top left, you should be able to see all of the label. It may not be where you want it though. Limiting to borders is a good idea.