Android Question Added new row in db - MySql Problem, PHP

WebQuest · Nov 13, 2019

Hi community I'm testing the functions to add a new Row in the db present on my server, I state that I am a beginner with php codes. I am editing a php script that I take as an example. I replaced the parameters for accessing the server with my access parameters, then I replaced the db with mine and modified the name of the table where I entered the parameters and fields to direct the new row to my db. The problem is that no addition to the db occurs and I get no error from the server and from the json log how can I solve it?

In the server error log this is this:
[13-Nov-2019 12:17:07 UTC] PHP warning: mysqli_error () has exactly 1 parameter, 0 given in /Directory/personsdb.php on line 9

I wanted to clarify that I use PhpMyAdmin for the db in Cpanel and that for reading the rows from my app it works.

SCRIPT PHP

Code:

  <?php
 $host = "localhost";
    $user = "xxxxxxx";     //parameters obscured by me
    $pw = "xxxxxxxxx;
    $db = "xxxxxxxxx";


    $con = mysqli_connect($host,$user,$pw) or die(mysqli_error());
    mysqli_select_db($con,$db) or die(mysqli_error());
    mysqli_query($con,"SET CHARACTER SET utf8");
    mysqli_query($con,"SET NAMES 'utf8'");

 
    $json = file_get_contents("php://input");
    $jsall = array();
    $jsone = array();
    $jsall=json_decode($json, true);
    $jsone=$jsall[0];
 
    $Action = $jsone["Action"];
 
    switch ($Action)
    {
 
    Case "InsertPerson":
 
                                                        $pname=stripslashes(mysqli_real_escape_string($con,$jsone["pname"]));
$pbirthdate=stripslashes(mysqli_real_escape_string($con,$jsone["pbirthdate"]));
 
        $stmt = $con->prepare("INSERT INTO Comande (Post,Id) VALUES (?,?)");
        $rc=$stmt->bind_param($pname, $pbirthdate);
        $rc=$stmt->execute();
 
       break;
   default:
        print json_encode ("Error: Function not defined (" . $action . ")");
    }
?>

B4a CODE

Code:

Public const Servername As String = "http://www.xxxxxx.com"
           Public const ScriptPath As String = "/xxxxx.php"

Code:

Sub  InsertNewPerson (JsonString As String) As ResumableSub
    Dim j As HttpJob
    j.Initialize("", Me)
    j.PostString(Servername & ScriptPath, JsonString)
    Wait For (j) JobDone(j As HttpJob)
    Log(j.GetString)
    Dim Result As String = j.GetString
    j.Release
    Return Result
End Sub


Sub Button1_Click

    Dim id As Int=2
    JsonList.Initialize
 
    Dim JsonRow As Map = CreateMap("Action":"InsertPerson","pname":EditText1.Text,"pbirthdate":id)
    JsonList.Add(JsonRow)
 
    JsonGenerator.Initialize2(JsonList)
    Dim JSONstring As String = JsonGenerator.ToString
 
    Wait For(InsertNewPerson(JSONstring)) Complete (Result As String)
    Log(Result)
 
End Sub

MarkusR · Nov 13, 2019

Example
https://www.w3schools.com/php/func_mysqli_error.asp

mysqli_error () has exactly 1 parameter, 0 given

it means it should look like mysqli_error($con)
u used it here

or die(mysqli_error())

should be mysqli_connect_errno()

there are different spellings, you can use the object.MethodName
or MethodName(object)

as Example
a.Close
Close(a)

WebQuest · Nov 14, 2019

Thanks for the answer I added the instruction ... and I found the problem, only now I can only enter int numeric characters. It happens that in the EditText I can insert on which column I want to write. I need to go through the EditText the string to add to the db how can I do? No I can detect in the example php where to act to indicate a fixed column and through the EditText pass the string

MarkusR · Nov 14, 2019

look at bind param types parameter
https://www.php.net/manual/de/mysqli-stmt.bind-param.php

WebQuest · Nov 14, 2019

Is there a more direct way to insert data into a db on a server? Could you show me an example?

Erel · Nov 15, 2019

Why aren't you using jRDC2? It is simpler and more powerful.

WebQuest · Nov 16, 2019

Hi Erel I thought about it but from what I understand jdrc2 needs a pc running the b4j server to work anywhere correct me if I'm wrong

DonManfred · Nov 16, 2019

Any pc which is able to run java apps. PC, Server, a VPS (even cheap ones).

WebQuest · Nov 16, 2019

So I could add the .bas b4j directly on the server?

DonManfred · Nov 16, 2019

No. a bas file will not "run" on your server. It must be a b4j server app (compiled) which is a jar file.

If your server is able to run java apps. https://www.b4x.com/android/forum/threads/server-run-a-server-on-a-vps.60378/
please create a new thread for any new question.

WebQuest · Nov 20, 2019

Hi DonManfred I read Erel's tutorial and it seems more complicated to me. So there is no solution with a php script to load data into a mysql db via a b4a app?

DonManfred · Nov 20, 2019

Lowegaterecords said:
So there is no solution with a php script to load data into a mysql db via a b4a app?

Sure it is. I always use PHP as bridge... You just need to do it right.

I can´t help you with the mysqli methods as i am using a mysqli class since many years.

WebQuest · Nov 20, 2019

The missing link is that I can't inherit data sent from the json in the script.

With fixed parameters I can add data to the db via app b4a input.
Do you know the get method to inherit json data in the php script?

Code:

<?php
$servername = "xxxxxxt";
$username = "xxxxxxt";
$password = "xxxxxxt";
$dbname = "xxxxxxt";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);

    mysqli_select_db($conn,$dbname) or die(mysqli_error());
    mysqli_query($conn,"SET CHARACTER SET utf8");
    mysqli_query($conn,"SET NAMES 'utf8'");
 
 
     if (mysqli_error($conn))
       {
        echo "Failed to connect to MySQL: " . mysqli_error();
       }
// Check connection

if (!$conn)
{
    die("Connection failed: " . mysqli_connect_error());
}
else
{
  
$sql = "INSERT INTO Comande (Id, Post)VALUES ('1', 'jhon')";
if (mysqli_query($conn, $sql))
{
    echo "New record created successfully";
}
    else
{
    echo "Error: " . $sql . "<br>" . mysqli_error($conn);
}
mysqli_close($conn);
}  
?>

DonManfred · Nov 20, 2019

Use post request. Send the values as single keyvalue pairs. Or post the complete json and parse the json in php.
Easier is to send keyvalue pairs (at least i am more familar with).

PHP:

if (isset($_REQUEST['orderID'])){$userID=intval($_REQUEST['userID']);} else {$userID=0;}
  if (isset($_REQUEST['name'])){$orderID=$_REQUEST['name']);} else {$name="";}

WebQuest · Nov 20, 2019

I'm currently trying to send a couple with a b4a app via a map like this.

Code:

Sub  InsertNewPerson (JsonString As String) As ResumableSub
    Dim j As HttpJob
    j.Initialize("", Me)
    j.PostString(Servername & ScriptPath, JsonString)
    Wait For (j) JobDone(j As HttpJob)
    Log(j.GetString)
    Dim Result As String = j.GetString
    j.Release
    Return Result
End Sub


Sub Button1_Click

    Dim id As Int=1
    Dim JsonRow1 As Map = CreateMap("Id":id,"Post":EditText1.Text)
   
    JsonGenerator.Initialize(JsonRow1)
    Dim JSONstring As String = JsonGenerator.ToString
   
    Wait For(InsertNewPerson(JSONstring)) Complete (Result As String)
    Log(Result)

End Sub

This example from the php manual encodes the php data in json how do I get the opposite?

Code:

$ myObj-> city = "New York" ;

$ myJSON = json_encode ($ myObj);

DonManfred · Nov 20, 2019

Lowegaterecords said:
encodes the php data in json how do I get the opposite?

json_decode?

Brandsum · Nov 20, 2019

B4A Code:

Code:

Sub  InsertNewPerson (data As Map) As ResumableSub
    Dim j As HttpJob
    j.Initialize("", Me)
    j.PostMultipart(Servername & ScriptPath, data,Null)
    Wait For (j) JobDone(j As HttpJob)
    Log(j.GetString)
    Dim Result As String = j.GetString
    j.Release
    Return Result
End Sub

Sub Button1_Click
    Dim id As Int=2
    Dim data As Map = CreateMap("Action":"InsertPerson","pname":EditText1.Text,"pbirthdate":id)
    Wait For(InsertNewPerson(data)) Complete (Result As String)
    Log(Result)
End Sub

PHP Code:

PHP:

<?php
 $host = "localhost";
    $user = "xxxxxxx";     //parameters obscured by me
    $pw = "xxxxxxxxx";
    $db = "xxxxxxxxx";


    $con = mysqli_connect($host,$user,$pw) or die(mysqli_error());
    mysqli_select_db($con,$db) or die(mysqli_error());
    mysqli_query($con,"SET CHARACTER SET utf8");
    mysqli_query($con,"SET NAMES 'utf8'");

    $Action = $_POST["Action"];
   
    switch ($Action)
    {
 
        case "InsertPerson":
            $pname=stripslashes(mysqli_real_escape_string($con,$_POST["pname"]));
            $pbirthdate=stripslashes(mysqli_real_escape_string($con,$_POST["pbirthdate"]));
   
            $stmt = $con->prepare("INSERT INTO Comande (Post,Id) VALUES (?,?)");
            $rc=$stmt->bind_param($pname, $pbirthdate);
            $rc=$stmt->execute();
   
           break;
       default:
            print json_encode ("Error: Function not defined (" . $action . ")");
    }
?>

Android Question Added new row in db - MySql Problem, PHP

WebQuest

Active Member

MarkusR

Well-Known Member

WebQuest

Active Member

MarkusR

Well-Known Member

WebQuest

Active Member

Erel

B4X founder

WebQuest

Active Member

DonManfred

Expert

WebQuest

Active Member

DonManfred

Expert

WebQuest

Active Member

DonManfred

Expert

WebQuest

Active Member

DonManfred

Expert

WebQuest

Active Member

DonManfred

Expert

Brandsum

Well-Known Member

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