Android Question Choose a random between 4 strings

SMOOTSARA

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How can I print one of these 4 items by chance?🌹


B4X:
Dim str1() As String
str1 = Array As String("no", "yes","ooo","test","yyy","nnn")
Log(?????????)

πŸ™ πŸ™
 

Star-Dust

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B4X:
Dim str As String = Regex.Split(",","no,yes,ooo,test,yyy,nnn")(rnd(0, 6))
 
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udg

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Mine is better
This one is even better :D
B4X:
Dim str1() As String = Array As String("no", "yes","ooo","test","yyy","nnn")
Log(str1(rnd(0, str1.Length)))
No unused vars (str and Index as from #2 and #3 above) .. :D
 
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Mahares

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If we are tabulating the number of ways, here is another:
B4X:
Dim MyList As List
MyList.Initialize
MyList.AddAll(Array ("no", "yes","ooo","test","yyy","nnn"))
Log(MyList.Get(Rnd(0, MyList.Size)))
 
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Star-Dust

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The second code generates an static collection and therefore it will no longer be possible to add or remove elements
 
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Star-Dust

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I would add that the array brings together data of the same type, while in the list you could put different data type
 
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Erel

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I would add that the array brings together data of the same type, while in the list you could put different data type
That's true if the array type is not Object (no type = Object).

No difference to me. They are the same:
Try:
B4X:
Dim MyList As List = Array ("no", "yes","ooo","test","yyy","nnn")
MyList.Add("Mahares")
 
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Mahares

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Try:
B4X:
Dim MyList As List = Array ("no", "yes","ooo","test","yyy","nnn")
MyList.Add("Mahares")
I was under the impression that when you use : MyList.set(.., you are actually removing and adding at the same time to come up with the 'replace'. Apparently, that is not the case with list.
 
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