Bug? regex single char split

[sorex]

I don't know if this is a bug in a library or default behaviour in Java
but this seems suspicious and it's not the output I got in several other languages.

Log ( hours )
Log ("!" & DateTime.GetHour(DateTime.Now) &"!")
Log ( "0:" & Regex.Split("",DateTime.GetHour(DateTime.Now))(0) )
Log ( "1:" & Regex.Split("",DateTime.GetHour(DateTime.Now))(1) )
Log ( "2:" & Regex.Split("",DateTime.GetHour(DateTime.Now))(2) )
Log ( "C:" & Regex.Split("",DateTime.GetHour(DateTime.Now)).Length)

the output is:

19
!19!
0: <- should be 1
1:1 <- should be 9
2:9 <- should not exist
C:3 <- should be 2

the value in the array at position 0 should not even exist since there is no leading space (the !19! proves this)

 

[Erel]

This is how the underlying Regex engine behaves. What is the purpose of splitting text with an empty string as the separator???

 

[sorex]

that will make an array of each individual charater, so it's easy to find/fetch the right char.

I know you can do the same with substr but I use(d) split/explode a lot so it's kind of a habbit to stick to it

I'll keep in mind that the empty split starts at 1 instead of the traditional 0 in the array
(works fine (pos 0 in the array) with the none empty split, just tested this)

 

[Erel]

You can use this code:

For i = 0 To SomeString.Length - 1
 Dim c As Char = SomeString.CharAt(i)
Next

 

[sorex]

that's my point, why use a loop when 1 command does the same?

(Ok internally it probably uses the same trick anyway)